 Friends         |  Idonthaveausername: HAPPY FATHER'S DAY TO THE BEST DADDY EVAAAAAAH. THANK YOU SO MUCH FOR SUPPORTING ME AND CARING ABOUT MY WELL BEING. YOU ARE AN AWESOME DAD. AND I LOVE IT WHEN WE DO MATH TOGETHER!!! THAT'S SOME GOOD OL' DADDY DAUGHTER BONDING. HIP HIP HORRAY!!!! ^_^ 8 years ago • Report • Link 0 View all 4 posts  Idonthaveausername in reply to Drakez: Lol xD You were so excited to see your daddy too.... Awww ^_^  Fernando_lifter: Greetings for you, Lovecraftian God. Do the things that a logical god is able to do  Nyarlathotep_: I got nerd sniped by the user questions answers He proposed an interesting problem, I'm going to rephrase it, but it is the same problem: X of your friends are going to play games of chess at the park. Also there are strangers playing chess games at the park. All of your friends win exactly Y chess games. All of your friends lose exactly Z chess games. We want to know the minimum and maximum number of games that must be played to have this outcome. To be clear, we will only count games where one or more of your friends play. And your friends are allowed to play strangers or each other. No games are ever drawn. What is the minimum number of games that must be played to satisfy the conditions (expressed in terms of x,y, and z)? What is the maximum number of games that could be played to satisfy the conditions (expressed in terms of x,y, and z)? I've got a solution that I think is correct, I'd like to see what other people come up with. Idonthaveausername: Lets say there are 10 friends (X). Those friends won 15 games and lost 10 games. This men that played a total of 25 games each. Therefore a total of 250 games were played, at the minimum. That's if, it was a perfect case. 250= 10(15+10) Number of games is equal to the total of wins Y and loses Z times the number of friends X. Now lets reduce to smaller numbers: 5 friends X, 3 wins Y,1 loss Z: here is a chart Win Loss Next Game wins Next Game losses 1 3 1 4 1 2 3 1 3 2 3 3 1 3 2 4 3 1 4 1 5 3 1 3 2 Look at the wins and losses for now. We have 4 games by 5 people so that's 20 games total. Now lets put in one more game. Go back and look at the Results of the next game. They no longer have the same amount of wins and loses which is needed by the scenario. So, they will have to play more games until the number balances out. (Post deleted by staff ) |
